This is so much fun but you need time to think!!!!

A Professor at a Nigerian University sent his phone number in a disorderly manner to his students. The disordered phone number was 64001128454.*

To know his real phone number, he gave the students the following conditions:

1. Eight (8) must come between two zeros (0 s).

2.The first number after the first condition must not be an odd number and it must be greater than 5.

3. The seventh number must be 1.

4. The fifth and sixth numbers must be two numbers whose difference is 1 and the bigger number must come first.

5. The fifth and sixth numbers are greater than 2.

6. The ninth and tenth numbers are the same.

7. The eighth number is greater than the last number.

8. The phone number must be 11 digits.

*What is the Professor's real phone number?*

Make we see if our brain still sharp

I no dey play this kain game. Na only candy crush I sabi π

ReplyDelete08065412441

ReplyDeleteCorrect!

Delete0806541442

ReplyDeleteN

The professor's phone number is 08065412441.

ReplyDeleteI eat mathematics.

ReplyDeleteMy name is Uptown π

His real phone number is

0 8 0 6 2 1 1 5 4 4 4

1. 080

2. 6

3. 1

4. 2 and 1

5. 2 + 1= 3 and 3 > 2

6. 4 and 4

7. 5 > 4

8. 08062115444

ππ€

You don't need to 'eat' mathematics to know this biko. It's quite simple.

DeleteI no fit oo

ReplyDelete0806651...π΄

ReplyDelete6 0 8 0 5 4 1 2 4 4 1

ReplyDeleteTook me all of 3 minutes. This was fun! Please more of this.

And i failed woefully lmao... The crisis of overconfidence.

DeleteThe diff between wrong and right might have been an extra minute.

DeleteSnarker you are the only person that got the Professor's number correctly.

Delete1st Clue--- 8 must come btw two zeros (080)but this doesn't make them come first.

2nd clue---1st number must not be an odd number and must be greater than 5. Best Option is number 6. With that, I have----- 6080

3rd clue--- 7th number is 1, I have------ 6080--1----

4th Clue--- 5th and 6th number have difference of 1 and bigger number comes first, best options are 5 and 4. With this I have----- 6080541----

5th Clue--- 5th and 6th number are greater than 2 which is valid above.

6th Clue--- 9th and 10th number are same. best possible options are 4 & 4, We then have, 6080541-44-

7th Clue--- The 8th number is greater than the last number. Two numbers are left which are 1 & 2. 2 is greater than 1, which maks 1 the last number and 2 the eight number.

We then finally have 60805412441 and it is 11.

Thank you.

Anon 18:59, you and snarker are wrong.

DeleteThe second clue says; the first number "after" the first condition meaning after 080

08052116444

ReplyDelete08065411441

Delete08065412441

ReplyDeleteThe Professor's real phone number is 08065412441

ReplyDelete08065412441

ReplyDelete08065412441ππππ

ReplyDelete08065412441

ReplyDeleteThe phone number is 08065412441

ReplyDelete1) 080

2) 6 (6 is an even number and is

greater than 5)

3) 1

4) 5 & 4 (the diff btw them is 1 and

5 is greater than 4)

5) 5 & 4 (are greater than 2)

6) 4, 4 (both are the same)

7) 2 (it is greater than the last

number)

8) 1 (is the last number)

08065412441

ReplyDeleteWetin be first condition π³π³

ReplyDelete080 (eight between two zeros)

DeleteAll I have to say is... No one should call professor ooh. Strolls away

ReplyDeleteDon't even stress my self

ReplyDeleteI no do abeg

08065412441

ReplyDelete08062115444

ReplyDelete08062115444

ReplyDelete08065412441π

ReplyDelete08065412441

ReplyDeleteStella please publish the answers to all this your riddles/ mathematics so that we can be sure we are correct.. Dalu

ReplyDelete08065412441. not that difficult

ReplyDelete08065412441

ReplyDelete08021541644

ReplyDelete